Answer:
Step-by-step explanation:
This will be a sum of two geometric sequences, one for distance falling and one for distance rising. The sum of a geometric sequence is expressed as s=a(1-r^n)/(1-r) where a=initial term, r=common ratio, and n= number of terms.
For the falling distance we have
f=3(1-.5^n)/(1-.5) as n goes to infinity it is just f=3/(.5)
For rising distance we have
r=1.5(1-.5^n)/(1-.5) and again as n goes to infinity it is r=1.5/(.5)
So the total distance travelled is
d=f+r
d=3/0.5+1.5/0.5
d=6+3
d=9 meters
