Solution :-
Area of rhombus :-
[tex] \bf \star \: \: \boxed{ \bf \dfrac{d_{1}d_{2}}{2} }[/tex]
[tex] \sf \longrightarrow d_{1} = 4 \sqrt{3} + 4 \sqrt{3} = 8 \sqrt{3} [/tex]
[tex] \sf \longrightarrow d_{2} = 4 + 4 = 8[/tex]
Area of rhombus :-
[tex] : \implies \sf \dfrac{8 \sqrt{3} \times 8 }{2} [/tex]
[tex] : \implies \sf 8 \sqrt{3} \times 4[/tex]
[tex]: \implies \bf 32 \sqrt{3} \: {m}^{2} [/tex]
