bambibrookes2002 bambibrookes2002
  • 10-03-2021
  • Chemistry
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Enter your answer in the provided box.

Calculate the volume (in liters) occupied by 2.35 moles of nitric oxide (NO) at 6.18 atm and 63°C.

L

Respuesta :

samueladesida43
samueladesida43 samueladesida43
  • 15-03-2021

Answer:

10.5L

Explanation:

The volume in this question can be calculated by using the formula for gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (litres)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the provided information in this question:

P = 6.18 atm

V = ?

n = 2.35 moles

R = 0.0821 Latm/molK

T = 63°C = 63 + 273 = 336K

Using PV = nRT

V = nRT/P

V = 2.35 × 0.0821 × 336/ 6.18

V = 64.83/6.18

V = 10.49

V = 10.5L

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