Answer:
The right answer is "58.3%".
Explanation:
The given values are:
Mass of lithium carbonate,
= 700 mg
i.e.,
= 0.7 g
Mass of tablet,
= 1.20 g
Now,
The percentage of active ingredient will be:
= [tex]\frac{Mass \ of lithium \ carbonate}{Mass \ of \ tablet}\times 100[/tex]
On substituting the given values, we get
= [tex]\frac{0.7}{1.20}\times 100[/tex]
= [tex]0.583\times 100[/tex]
= [tex]58.3[/tex]%
