Answer:
1.175 M
Explanation:
The balanced reaction is:
- H₂SO₄(aq) + 2KOH(aq) —> K₂SO₄(aq) + 2H₂O(l)
First we calculate how many moles of KOH reacted, using the given concentration and volume:
- 1.00 M * 23.5 mL = 23.5 mmol KOH
Then we convert moles of KOH to moles of H₂SO₄, using the stoichiometric coefficients of the balanced reaction:
- 23.5 mmol KOH * [tex]\frac{1molH_2SO_4}{2molKOH}[/tex] = 11.75 mmol H₂SO₄
Finally we calculate the molarity of the acid:
- 11.75 mmol H₂SO₄ / 10.0 mL = 1.175 M
