Answer:
9
Explanation:
n-factor of NaOH = 1
OH⁻ concentration = Normality of NaOH
= Molarity x n-factor
= 10⁻⁵ x 1
= 10⁻⁵
Now, pOH = -㏒(OH⁻)
pOH = -㏒(10⁻⁵)
pOH = 5
We know pH + pOH = 14
pH = 14 - 5 = 9
∴pH of 10⁻⁵M NaOH is 9
