Answer:
A=(0,0), B=(b,0), C=(b+c,d), D=(c,d) Then Using the distance formula
DC=√(c-[b+c])2+(d-d)2 DC=√b2 DC=b AB=√(0-b)2+(0-0)2 AB=√(-b)2 AB=√b2 AB=b then DC=AB DA=√(c-0)2+(d-0)2 DA=√c2+d2 CB=√(b+c-b)2+(d-0)2 CB=√c2+d2 then DA=CB
Step-by-step explanation:
