Answer:
92.26% of C
Explanation:
To solve this problem we must assume we have 1 mole of benzene. The mole contains 6 moles of C and 6 moles of H. We have to convert these moles to grams in order to find the total mass and mass percent will be:
Mass atom / Total mass * 100
Mass C: 6mol C * (12.0107g / mol) = 72.0642g
Mass H: 6mol H * (1.00794g / mol) = 6.04764g
total mass: 72.0642g + 6.04764g = 78.11184g
Mass percent of C will be:
72.0642g C / 78.11184g* 100
92.26% of C
