Answer:
[tex]for \: independent \: events : \\ P(AUB) = P(A) + P(B) \\ P(AUB) = \frac{2}{3} + \frac{1}{5} \\ = \frac{13}{15} [/tex]
Step-by-step explanation:
P(AUB) is P(A) + P(B) because P(AnB) is zero.
[tex]P(AUB) = P(A) + P(B) - P(A{ \huge{n} }B) \\ P(AUB) = P(A) + P(B) + 0[/tex]
