Answer:
[tex]\huge\boxed{p^3+p^2=p^2(p+1)}[/tex]
Step-by-step explanation:
[tex]p^3+p^2\\\\p^3=p^{2+1}=p^2\cdot p\\\\p^3+p^2=p^2\cdot p+p^2\cdot1=p^2(p+1)[/tex]
Used:
[tex]a^n\cdot a^m=a^{n+m}\\\\\text{distributive property}:\ a(b+c)=ab+ac[/tex]
