[tex] \large{f(x) = g(x)} \\ \large{ {x}^{2} + 3x = x + 3}[/tex]
Since we are solving the quadratic equation because the highest degree in the equation is second. We arrange in the form of ax²+bx+c = 0.
[tex] \large{ {x}^{2} + 3x - x - 3 = 0}[/tex]
Combine like terms.
[tex] \large{ {x}^{2} + 2x - 3 = 0}[/tex]
Solve the equation by factoring.
[tex] \large{(x + 3)(x - 1) = 0} \\ \large{x = - 3,1}[/tex]
Hence the values of x that make f(x) = g(x) are -3 and 1.
Answer
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