Answer:
[tex] {x}^{2} + 2x + 1 = 17 \\ {x}^{2} + 2x - 16 = 0 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 2± \sqrt{68} }{2} \\ x = \frac{ - 2±2 \sqrt{17} }{2 } \\ x = - 1± \sqrt{17} [/tex]
