please, you have to apply the formula below:
Q=c∗m∗Δt
where Q is the energy lost,
c is the specific heat of water,
m is the mass of water involved,
so m=3.75 *10^-1 Kg
c=4,184 J/(Kg*°C)
delta t=37.5 °C
I hope my answer has come to your help. God bless and have a nice day ahead!
