Answer:
true ...
believe it or not there is an exponential sequence that can make that
result
f(x) = [tex]2^{(2(x+2) -1)}[/tex]
x /// 2(x+2) -1
-1 /// 1
0 /// 3
1 /// 5
2 /// 7
[tex]2^{1} = 2\\2^{3} = 8\\\\2^{5} = 32\\\\2^{7 = 128\\\\[/tex]
Step-by-step explanation:
