Answer:
[tex]120.\sqrt{2}.\sqrt[3]{3}[/tex]
Step-by-step explanation:
[tex]\sqrt{32} = \sqrt{16.2} =\sqrt{4^{2}.2} = 4\sqrt{2}[/tex]
[tex]\sqrt[3]{81} =\sqrt[3]{27.3} =\sqrt[3]{3^{3}.3 }=3\sqrt[3]{3}[/tex]
∴[tex]5\sqrt{32}.2\sqrt[3]{81} =5. [4\sqrt{2}].2.[3\sqrt[3]{3} ][/tex]
[tex]=120.\sqrt{2}.\sqrt[3]{3}[/tex]
