yesirr56
yesirr56 yesirr56
  • 08-07-2021
  • Mathematics
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Helppppp and explain pls and thankyou

Helppppp and explain pls and thankyou class=

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kamilmatematik100504
kamilmatematik100504 kamilmatematik100504
  • 08-07-2021

[tex]\displaystyle\ (\sqrt{25x-16} )^2=\ (i)^2 \\\\ 25x-16=-1 \\\\25x=15\\\\\boxed{x=\frac{3}{5}}[/tex]

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