Answer:
4(x - [tex]\frac{1}{2}[/tex] )² = 0
Step-by-step explanation:
Given
4x² - 4x + 1 = 0 ( factor out 4 from the first 2 terms )
4(x² - x) + 1 = 0
To complete the square
add/subtract ( half the coefficient of the x- term)² to x² - x
4(x² + 2(- [tex]\frac{1}{2}[/tex] )x + [tex]\frac{1}{4}[/tex] - [tex]\frac{1}{4}[/tex] ) + 1 = 0
4(x - [tex]\frac{1}{2}[/tex] )² - 1 + 1 = 0
4(x - [tex]\frac{1}{2}[/tex] )² = 0
