Answer:
[tex]x = \dfrac{1 + i\sqrt{47}}{6}[/tex] or [tex]x = \dfrac{1 - i\sqrt{47}}{6}[/tex]
Step-by-step explanation:
[tex] x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]
We have a = 3; b = -1; c = 4.
[tex] x = \dfrac{-(-1) \pm \sqrt{(-1)^2 - 4(3)(4)}}{2(3)} [/tex]
[tex]x = \dfrac{1 \pm \sqrt{1 - 48}}{6}[/tex]
[tex]x = \dfrac{1 \pm \sqrt{-47}}{6}[/tex]
[tex]x = \dfrac{1 + i\sqrt{47}}{6}[/tex] or [tex]x = \dfrac{1 - i\sqrt{47}}{6}[/tex]
