Step-by-step explanation:
Set up f(x).
[tex] \sqrt[3]{11x - 3} = f(x)[/tex]
Replace f(x) with y
[tex] \sqrt[3]{11x - 3} = y[/tex]
Swap x and y
[tex] \sqrt[3]{11y - 3} = x[/tex]
Solve for y
Cube both sides
[tex]11y - 3 = {x}^{3} [/tex]
Add 3 to both sides
[tex]11y = {x}^{3} + 3[/tex]
Divide both sides by 11
[tex]y = \frac{x {}^{3} + 3 }{11} [/tex]
so
[tex]f {}^{ - 1} (x )= \frac{ {x}^{3} + 3}{11} [/tex]
