tiyalama492 tiyalama492

08-08-2021
Mathematics

contestada

x^2+4xy+4y^2-8x-16y-20

Respuesta :

surjithayer10otahza surjithayer10otahza

08-08-2021

Answer:

Step-by-step explanation:

x²+4xy+4y²-8x-16y-20=(x+2y)²-8(x+2y)-20

put x+y=t

t²-8t-20=t²-10t+2t-20=t(t-10)+2(t-10)=(t-10)(t+2)

substitute the value of t

x²-4xy+4y²-8x-16y-20=(x+2y-10)(x+2y+2)

i don't know what else you want.

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