Answer:
sinE = [tex]\frac{3}{5}[/tex]
Step-by-step explanation:
To find sinE we require DF
Using Pythagoras' identity in the right triangle
DF² = EF² - DE² = 10² - 8² = 100 - 64 = 36 ( take square root of both sides )
DF = [tex]\sqrt{36}[/tex] = 6
Then
sinE = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{DF}{EF}[/tex] = [tex]\frac{6}{10}[/tex] = [tex]\frac{3}{5}[/tex]
