Respuesta :

wegnerkolmp2741o

Answer:

nj+k = p

Step-by-step explanation:

n = (p-k)/j

Multiply each side by j

nj = (p-k)/j *j

nj = p-k

Add k to each side

nj +k = p-k+k

nj+k = p
N = (p-k)/j // - (p-k)/j

N-((p-k)/j) = 0

(-1*(p-k))/j+N = 0


So it’s 0. Hope this helps!

(-1*(p-k))/j+(N*j)/j = 0

N*j-1*(p-k) = 0

N*j+k-p = 0

(N*j+k-p)/j = 0

(N*j+k-p)/j = 0 // * j

N*j+k-p = 0

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good job