yusraahussain05 yusraahussain05
  • 08-09-2021
  • Mathematics
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Evaluate the limit (picture)

Evaluate the limit picture class=

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LammettHash
LammettHash LammettHash
  • 08-09-2021

π ≈ 3.14 > 2, so the second piece is the relevant one:

[tex]\displaystyle \lim_{x\to\pi}f(x) = \lim_{x\to\pi}\sin(x) = \sin(\pi) = \boxed{0}[/tex]

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