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A vector starts at point ( -3, 8) and ends at point (-2, 2) what is the horizontal component of the vector?


A vector starts at point ( 1, 9) and ends at point (6, -5) what is the magnitude of the vector, answer to two decimal places.


A vector starts at point ( -1, -10) and ends at point (8, -8) what is the vertical component of the vector?


Please help me! it would be greatly appreciated

Respuesta :

Answer:  Hi! I'm sorry this answer is late but if you're still wondering, I think this is the answer . Please let me know if it works for you.

Step-by-step explanation:

Question 1.

So, The question asks us for the Horizontal Component.

The Horizontal component is simply 'x' in a plane coordinate or (x,y).

So, first we have to recognize the Initial and Terminal Point. For this vector it is:

Initial Point(Starting point): (-3,8) Terminal Point(End point): (-2,2).

To find components given the Initial and Terminal points in coordinates, the formula is as follows: x-coordinate Terminal minus x-coordinate Initial and  y-coordinate Terminal minus y-coordinate initial. Or in other terms : (Xₜ-Xᵢ, Yₜ-Yᵢ)  

To find the Horizontal Component it would look like this:

Xₜ-Xᵢ:  -2- (-3)  -------->  -2+3 = 1 (If you're wondering why the sign changed to addition it's because 2 negative signs adjacent to each other change to addition per integer rules. An example:  -5-(-7)  -----> -5+7 ). So, 1 is your horizontal component.

Question 2.  

In order to find the magnitude of a vector, you must know the Terminal and Initial Points because Magnitude = Terminal - Initial.  

Terminal: (6, -5)    Initial: (1, 9)  

Remember the Formula (Xₜ-Xᵢ, Yₜ-Yᵢ)  

6-1 = 5   |      -5-9 = -14

We just found the horizontal and vertical components.

Now we use pythagoreans theorem to find the magnitude.

5²+-14² = c²  ------>  25+ 196 = c²  -------->  221 = c²  ------->  √ 221 =  √ c²    

c² = 14. 86606875  or 14.87 if rounded.

Question 3.

This question is asking us what the vertical component of the vector is.

Terminal: (8,-8) Initial: (-1,-10)

Remember the Formula (Xₜ-Xᵢ, Yₜ-Yᵢ)  

Vertical Component: ( -8 - (-10) -----> -8 +10 = 2

Horizontal component: (8-(-1)) ------> 8+1 = 9

Once again, I hope this helps. Sorry it took so long and I wish you all the best of luck in school. Have a blessed day.

Using vector concepts, it is found that:

  • 1. The horizontal component of the vector is 5.
  • 2. The magnitude is of 14.87.
  • 3. The vertical component of the vector is 2.

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  • A vector (x,y) has x as horizontal component and y as vertical component.
  • The magnitude is [tex]M = \sqrt{x^2 + y^2}[/tex]
  • Given two points, a vector is formed by the subtraction of the endpoint by the start point.

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Item 1:

  • The horizontal component of the start is -3.
  • The horizontal component of the end is 2.
  • Thus, the horizontal component of the vector is [tex]2 - (-3) = 2 + 3 = 5[/tex]

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Item 2:

  • Starts at (1,9), ends at (6,-5), thus, the coordinates are:

[tex](6,-5) - (1,9) = (6-1, -5 - 9) = (5, -14)[/tex]

The magnitude is:

[tex]\sqrt{5^2 + (-14)^2} = \sqrt{25 + 196} = \sqrt{221} = 14.87[/tex]

The magnitude is of 14.87.

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Item 3:

  • The vertical component of the start is -10.
  • The vertical component of the end is -8.
  • Thus, the vertical component of the vector is [tex]8 - (-10) = -8 + 10 = 2[/tex]

A similar problem is given at https://brainly.com/question/24606590

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