Molarity as Stoikiometri
Equatuions od Molarity :
M = m/Mr × 1000/V
Mr Lithium Dichromate (Li2CrO4)
= Ar Li (2) + Ar Cr + Ar O (4)
= 7 (2) + 52 + 16 (4)
= 14 + 52 + 64
= 130 g/mol
Molarity
= m/Mr × 1000/V
= 19.5 g/130 g/mol × 1000/95 mL
= 0.15 mol × 10.53 /L
= 1.5795 mol/L
So, the molarity of the solution is 1.5795 mol/L
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