Respuesta :

Answer:

x>2 or (2,∞)

Step-by-step explanation:

if x≤2, 3*|2-x| = 3*(2-x) = 6-3x

3*|2-x| +3x-6 = (6-3x) + 3x-6 = 0  ... f(x) -> ∞   denominator = 0

if x>2, 3*|2-x| = 3*-(2-x) = -6+3x

3*|2-x| +3x-6 = (-6+3x) + 3x-6 = 6x - 12 >0

good job