Respuesta :

discipulus

Answer:

[tex]x + 3y = 5...(1) \\ 2x + y = 8...(2) \\ 2 \times (1) \\ 2x + 6y = 5...(3) \\ (3) - (2) \\ 5y = 5 \\ y = \frac{5}{5} \\ \color{red} \boxed{y = 1} \\ sub \: in \: (1) \\ x + 3(1) = 5 \\ x = 5 - 3 \\ \color{blue} \boxed{x= 2}[/tex]

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