Seudónimo Seudónimo
  • 10-01-2017
  • Mathematics
contestada

Factor jm + jn + km + kn.
a) (j + k)(m + n)
b)(j + m)(n + k)
c) (n + j)(k + m)

Respuesta :

kristy0
kristy0 kristy0
  • 10-01-2017
a, (j+k)(m+n)  you take the j out and then the k
Answer Link
Аноним Аноним
  • 10-01-2017
jm + jn + km + kn
= j(m+n) +k(m+n)
=(m+n)(j+k)
answer is 
a) (j + k)(m + n) 
Answer Link

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