TionaDavis
TionaDavis
11-01-2017
Mathematics
contestada
how do you solve -5a^0×a^0 ?
Respuesta :
mileszsmith
mileszsmith
11-01-2017
Anything to the power of 0 is 1, so 1+1=2
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piradii2
piradii2
11-01-2017
-5 * a^0 * a^0 = -5 * 1 * 1 = -5
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good job