Respuesta :

loneguy

[tex]\text{Given that,}\\\\\text{First term,}~ a_1= -\dfrac 16\\\\\text{Common ratio,}~ r = 2 \\\\\text{nth term}~ a_n = a_1 r^{n -1} = -\dfrac 16 \left(2^{n-1}\right)[/tex]

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good job