- Atomic weight of copper = 63.5 g
- 1 mole of copper contains = 63.5g = 6.023 × 10²³ atoms of copper
- 1 g of copper contains
- [tex] = \frac{ 6.023 \times 10²³}{63.5} [/tex]= 9.4 × 10²¹ atoms
- Therefore, 3.11g of copper contains
- [tex] = 3.11 \times 9.4 \times {10}^{21} \\ [/tex]
- = 29.234 × 10²¹ atoms
Hope you could get an idea from here.
Doubt clarification - use comment section.
