Let, p (x) = x^4 + 3x^3 - 8x^2 + kx + 16
When, x = 2 then,
Using remainder theorem,
p(x) = x^4 + 3x^3 - 8x^2 + kx + 16
p(2) = 2^4 + 3*2^3 - 8*2^2 +k*2 + 16
0 = 16 + 3*8 - 8*4 + 2k + 16
0 = 16 + 24 - 32 + 2k + 16
0 = 24 + 2k
2k = -24
◆ k = -12
It is right answer...
I hope you understand...
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