matteop7 matteop7

06-03-2022
Mathematics

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Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC.
Prove △GEC ≅ △HFA.

Given ABCDis a parallelogram GEC HFA and AE FC Prove GEC HFA class=

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Аноним Аноним

10-03-2022

<G E C=<H F A

A s

A E=F C
A F=E C

A lso

<CAH=<GCE

Hence

△GEC ≅ △HFA(ASA)

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