The work of a student to solve the equation 2(3x βˆ’ 4) = 8 + 2x + 4 is shown below:

Step 1: 2(3x βˆ’ 4) = 8 + 2x + 4
Step 2: 5x βˆ’ 6 = 12 + 2x
Step 3: 5x βˆ’ 2x = 12 + 6
Step 4: 3x = 18
Step 5: x = 6

In which step did the student first make an error and what is the correct step?

Step 2; 6x βˆ’ 6 = 2(6 + x + 2)
Step 2; 6x βˆ’ 8 = 12 + 2x
Step 3; 5x βˆ’ 2x = 12 βˆ’ 6
Step 3; 5x + 2x = 12 + 6