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The table represents quadratic function g. Which statement is true about the function?
I
-5
-4 -3
-2 -1 0
-1
0
-1
-4 -9 -16
O A. The minimum occurs at the function's x-intercept.
O B.
The maximum occurs at the function's x-intercept.
O C.
The maximum occurs at the function's y-intercept.
The minimum occurs at the function's y-intercept.
O D.

Respuesta :

Answer:

B. Β  The maximum occurs at the function's x-intercept.

Step-by-step explanation:

Given table:

[tex]\large\begin{array}{| c | c | c | c | c | c | c |}\cline{1-7} x & -5 & -4 & -3 & -2 & -1 & 0\\\cline{1-7} g(x) & -1 & 0 & -1 & -4 & -9 & -16\\\cline{1-7}\end{array}[/tex]

From inspection of the table, we can see that:

  • [tex]g(-5) = -1[/tex] Β and
  • [tex]g(-3) = -1[/tex]

This indicates symmetry. Β 

The line of symmetry is the mid-point between the two x-values.

Therefore, the line of symmetry is x = -4

The vertex (minima/maxima) is on the line of symmetry, therefore the vertex is at (-4, 0). Β As the function decreases as x β†’ 0, the vertex is a maximum.

As the y-value of the vertex is 0, the maximum occurs at the function's x-intercept.

Answer:

B

Step-by-step explanation:

Finding the line of symmetry :

β‡’ Two x-values have the same y-coordinate β†’ (-5) and (-3)

β‡’ This means the symmetry is exhibited and it lies between these 2 x-values

β‡’ Line of symmetry : x = -4

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Now, on plotting these points on a graph we see that this graph has a negative coefficient.

β‡’ This means this graph will have a maximum point as the vertex

β‡’ The vertex lies on the line of symmetry, hence the vertex (according to the graph and table) is (-4, 0)

Hence, we can say that the maximum occurs at the function's x-intercept.

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