Answer:
[tex]\textbf{B)}~ 2\sqrt{83}[/tex]
Step-by-step explanation:
[tex]\text{Apply Pythagorean theorem,}\\\\~~~~~~\text{Hypotenuse}^2 = \text{Base}^2 + \text{Perpendicular}^2\\\\\implies \left( 12 \sqrt 3\right)^2 = 10^2 + x^2\\\\\implies 144\cdot 3 = 100+x^2\\\\\implies 432 =100+x^2\\\\\implies 432-100=x^2\\\\\implies 332= x^2\\\\\implies x = \sqrt{332}\\\\\implies x=\sqrt{4 \times 83}\\\\\implies x = 2\sqrt{83}[/tex]
