Answer:
[tex]x= \dfrac{38}7[/tex]
Step by step explanation:
[tex]~~~~~~~\log_{10} 7 + \log_{10}(x-4) = 1\\\\\implies \log_{10}(7(x-4)) = \log_{10} 10~~~~~~~~~~~~~~~;[\log_b(mn) = \log_b m + \log_b n]\\\\\implies 7(x-4) = 10\\\\\implies 7x -28 = 10\\\\\implies 7x = 10 +28 \\\\\implies 7x = 38\\\\\implies x= \dfrac{38}7[/tex]
