The values of a, b, and c are -4,0 and 0 and the parabola opens downward with y-intercept (0,0).
we have
y=-4x^2
The quadratic equation in standard form is equal to
ax^2+bx+c=0
So,In this problem
a=-4, b=0 and c=0
The y-intercept is the value of y when the value of x is equal to zero
y=-4(0)^2=0
The y-intercept is the point (0,0)
The coefficient a is negative, therefore the parabola opens down.
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