beasteddemon0123 beasteddemon0123

09-02-2017
Mathematics

contestada

Find the dimensions of a rectangular piece of property that has a perimeter of 610 feet if the length is twenty feet more than two times the width

Respuesta :

Amanda4447 Amanda4447

13-02-2017

2L + 2W = 610L = 2W + 20 Substitute the second equation into the first: 2(2W + 20) + 2W = 610 Solve for W. 4W + 40 + 2W = 6106W = 570W = 95 Use the second equation to solve for L

Answer Link

Otras preguntas

Who among the following was convicted and sentenced to death for leaking bomb-making secrets to the communists?

Find the distance between two points (6,−4) and (−4,−4).

A company has invested $60,000 in machinery with a 5-year useful life. The machinery will have no salvage value, as the cost to remove it will equal its scrap v

how many numbers are between 99 and 1000 which occupies the digit 8 in a unit place

Calcula: t15 + t25 Si se sabe que: 26; 31; 36; 41; …

what are the differences between fee-for-service health care model and single payer health care model

______ is the process responsible for the situation above. This process can cause DNA to change in many ways. Three such ways are ______, _____, and _____.

Find the area of the following shapes:

commission earned but not received is debit or credit?

What document provides the structure for the U.S government

good job