Answer:
[tex]y=2sin(2(x-\pi))[/tex]
Step-by-step explanation:
The general equation of a sine function can be written as:
[tex]y=(Amplitude)sin({\frac{2\pi}{period})(x-shift)[/tex]
Now, we are given that the amplitude is [tex]2[/tex] and period is of [tex]\pi[/tex] with a horizontal shift of [tex]\pi[/tex] units, thus the general equation becomes
[tex]y=2sin(\frac{2\pi}{\pi})(x-\pi)[/tex]
[tex]y=2sin(2(x-\pi))[/tex]
which is the required general equation of a sine function.
