kellyspeakslouder kellyspeakslouder

07-03-2017
Mathematics

contestada

The length of a rectangle is 5yd less than twice the width, and the area of the rectangle is 52yd^2. Find the dimensions of the rectangle.

Respuesta :

Aliwohaish12 Aliwohaish12

07-03-2017

52 = (2*W - 5) * W
52 = 2*W^2 - 5*W
0 = 2*W^2 - 5*W - 52
0 = (2W - 13)*(W + 4)

2W - 13 = 0 or W + 4 = 0
W = 13/2 or W = -4

Width cannot be negative so discard W = -4

W = 13/2 L = 2*(13/2) - 5 = 13 - 5 = 8

Answer Link

Otras preguntas

Solve. {y=x−82x+3y=1 Use the substitution method. (5, −3) (4, −4) (0, −8) (2, −6)

There are 42 boys and 48 girls in the sixth grade and each student must be assigned a homeroom. Each homeroom should have the same number of boys and the same n

Can i put triple antibiotic ointment on my dog

HELLP!! Drag the signs and values to the correct locations on the image. Each sign and value can be used more than once, but not all signs and values will be us

What does the goverment of finland give all new mothers

What is the domain of y=4sin(x)?

What does the endocrine system consist of

A car manufacturer is reducing the number of incidents with the transmission by issuing a voluntary recall. During week 3 of the recall, the manufacturer fixed

-4x + 2(5x - 6) + 2x = 44

How many services are there in the United States? What are they, and what do they do?

good job