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10-03-2017
Chemistry

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What is the ΔG given the following? ΔH = 20 kJ/mol T = 15°C ΔS = .101 kJ/molK

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10-03-2017

∆G = ∆H-T∆S
=20×10^3-(15+273)(.101×10^3)
=20000-(288)(101)
=20000-29088
=-9088 joule = -9.088 kj

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