Respuesta :

[tex]\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta r^2}{2}\qquad \begin{cases} \theta=\textit{angle in radians}\\ r=radius\\ ----------\\ \theta=\frac{\pi }{10}\\ r=20 \end{cases}\implies A=\cfrac{\frac{\pi }{10}\cdot 20^2}{2}[/tex]
sarahbuzzelli64

Answer: C) 20π

Step-by-step explanation:

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