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naǫ
[tex]4y+16\ \textgreater \ -8 \ 4y\ \textgreater \ -8-16 \\ 4y\ \textgreater \ -24 \\ y\ \textgreater \ \frac{-24}{4} \\ y\ \textgreater \ -6 \\ \hbox{answer A}[/tex]
answer is A. y>-6
you have to subtract 16 and -8 Which gives you -24. then divide it by 4.

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