Lexilu121475 Lexilu121475

08-06-2017
Chemistry

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How many atoms are in 2.5 moles of beryllium atoms?

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dec77cat dec77cat

08-06-2017

n(Be)=2.5 mol
Nₐ=6.022*10²³ mol⁻¹

N=n(Be)*Nₐ

N=2.5 mol * 6.022*10²³ mol⁻¹ = 1.5055*10²⁴ atoms

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