We are asked to solve for the zeros of the given quadratic equation f(x) = 9x2 + 6x + 1. To solve this, first, we need to set the given equation into zero such as the succeeding solution is shown below:
0 = 9x2 + 6x +1
Perform factoring such as:
0 = (3x + 1) (3x + 1)
Solving for x1, we have:
3x + 1=0
3x = -1
x1 = -1/3
Soving for x2, we have:
3x +1=0
x = -1/3
Therefore, the zeroes of the given expression is both -1/3 for x1 and x2.
