shawana2227 shawana2227
  • 08-06-2017
  • Mathematics
contestada

Find the b3, b4, and b5 terms of the sequence: b_(n)=100b_(n-2)+(b_(n-1))^(2), b_(1)=2, b_(2)=5

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angelicdragon12
angelicdragon12 angelicdragon12
  • 08-06-2017
[tex]b_{n}=100b_{n-2}+b_{n-1}^2 \\ b_{1}=2 \\ b_{2}=5[/tex]

[tex]b_{3}=100b_{3-2}+b_{3-1}^2 \\ b_{3}=100b_{1}+b_{2}^2 \\ b_{3}=100(2)+5^{2} \\ b_{3}=200+25 \\ b_{3}=225[/tex]

[tex]b_{4}=100b_{4-2}+b_{4-1}^{2} \\ b_{4}=100b_{2}+b_{3}^{2} \\ b_{4}=100(5)+225^{2} \\ b_{4}=500+50625 \\ b_{4}=51125[/tex]

[tex]b_{5}=100b_{5-2}+b_{5-1}^{2} \\ b_{5}=100b_{3}+b_{4}^{2} \\ b_{5}=100(225)+51125^{2} \\ b_{5}=22500+2613765625 \\ b_{5}=2613788125 [/tex]

[tex]b_{3}=225[tex]
[tex]b_{4}=51125[tex]
[tex]b_{5}=2613788125[tex]
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