A box contains 144 marbles, which are either red or blue. if there are 3 times as many red marbles as there are blue marbles in the box, how many red marbles are in the box
Given: X: The blue marbles. 3X: The red marbles. A box contains 144 marbles. SOLVING: X + 3X = 144 4X = 144 X = [tex] \frac{144}{4}[/tex] X = 36 ===> The blue marbles.
If there are 3 times as many red marbles as there are blue marbles: 3(36) = 108 ===> The red marbles. SOLUTION
TESTING: [tex]36+108=144[/tex] [tex] \boxed{144}=\boxed{144}\quad\checkmark\ The\ value\ is\ correct.[/tex] GOOD LUCK...!!!
