07-07-2017
Mathematics

contestada

Divide the following complex numbers: (6-i)/(5+4i)

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nicolina nicolina

07-07-2017

(6-i)/(5+4i)=
Multiply both numerator and denominator by (5-4i):
(6-i)(5-4i)/(5+4i)(5-4i)=
(30-24i-5i+4i^2)/(5^2-16i^2)=
(30-29i+4i^2)/(25-16i^2)=
i^2 = -1
(30-29i+4×(-1))/(25-16×(-1))=
(26-29i)/41

Answer Link

evanesqueda750 evanesqueda750

22-04-2022

Answer:26/41 - 29/41 i

Step-by-step explanation:

Answer Link

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