Respuesta :
[tex]\bf sin(2\theta)=2sin(\theta)cos(\theta)\\\\
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sin(2x)-cos(x)\implies 2sin(x)cos(x)-cos(x)
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cos(x)[2sin(x)-1][/tex]
Answer:
cos(x)(2sinx -1 )
Step-by-step explanation:
sin 2x - cos x
WE use sin(2x) identity
sin(2x)= 2sin(x)cos(x)
now we plug in our given expression
sin 2x - cos x
2sin(x)cos(x)- cos(x)
we factor out cos(x)
when we factor out cos(x), divide each term by cos(x)
cos(x)(2sinx -1 )
we got the final answer in terms of sinx and cosx
